The scale for the drawing of a rectangular playing field is 2 inchesequals3 feet. Find an equation you can use to find the dimensions of the actual field. What are the actual​ dimensions?

length
width
12 in.
6 in.

Find an equation you can use to find the dimensions of the actual field.
Use the equation y= __x, where x is a dimension of the scale drawing​ (in inches) and y is the corresponding dimension of the actual field​ (in feet).

1 answer

To derive an equation that connects the dimensions from the scale drawing to the actual dimensions of the rectangular playing field, we start with the given scale: 2 inches on the drawing corresponds to 3 feet in reality.

We can find the conversion factor by setting up a proportion based on the scale:

\[ \frac{\text{actual feet}}{\text{drawing inches}} = \frac{3 \text{ feet}}{2 \text{ inches}}. \]

To find the relationship between the dimensions of the scale drawing (in inches) and the actual dimensions of the field (in feet), we can express it in the form \(y = mx\), where:

  • \(y\) is the actual dimension in feet,
  • \(x\) is the dimension in inches,
  • \(m\) is the conversion factor.

From the scale, we can see that:

\[ m = \frac{3 \text{ feet}}{2 \text{ inches}} = 1.5 \text{ feet per inch}. \]

Thus, the equation that relates the dimension in inches to the actual dimension in feet is:

\[ y = 1.5x. \]

Next, we can use this equation to find the actual dimensions of the playing field given its dimensions from the scale drawing:

  • Length from the drawing: \(12\) inches
  • Width from the drawing: \(6\) inches

Now we can calculate the actual length and width using the equation \(y = 1.5x\).

  1. Actual Length: \[ y = 1.5 \times 12 = 18 \text{ feet}. \]

  2. Actual Width: \[ y = 1.5 \times 6 = 9 \text{ feet}. \]

Final Answer:

  • The equation is \(y = 1.5x\).
  • Actual Length: 18 feet.
  • Actual Width: 9 feet.