The scale drawing of the rectangular classroom floor has dimensions of 8 inches by 5 inches. The actual length of the longer side of the floor is 32 feet.

Question

What is the actual area of the floor in square feet?

A. 40 feet^2

B. 240 feet^2

C. 640 feet^2

D. 92,160 feet^2

Show your work for this problem. Be sure to show each step and explain using math vocabulary.

Answer 1

First, we need to determine the scale factor used in the drawing. To do this, we divide the actual length of the longer side by the length shown in the drawing:

32 feet / 8 inches = 48

This means that each inch in the drawing represents 4 feet in reality (48 inches in 32 feet).

Next, we calculate the actual width of the floor by multiplying the width shown in the drawing by the scale factor:

5 inches * 4 feet/inch = 20 feet

Now that we have the actual dimensions of the floor (32 feet by 20 feet), we can calculate the actual area of the floor by multiplying the actual length by the actual width:

32 feet * 20 feet = 640 feet^2

Therefore, the actual area of the floor in square feet is:

C. 640 feet^2.

Answer 2

simplify the explanation

Answer 3

First, we determined the scale factor by dividing the actual length of the longer side (32 feet) by the length shown in the drawing (8 inches). We found that each inch in the drawing represents 4 feet in reality.

We then multiplied the width shown in the drawing (5 inches) by the scale factor to find the actual width of the floor, which is 20 feet.

Finally, we calculated the actual area of the floor by multiplying the actual length (32 feet) by the actual width (20 feet), giving us an actual area of 640 square feet.

Therefore, the answer is C. 640 square feet.

Answer 4

Shorten it as well

Answer 5

We found the scale factor by dividing the actual length by the length on the drawing. Then, we multiplied the width on the drawing by the scale factor to get the actual width. Multiplying the actual length by the actual width gave us the actual area of 640 square feet. So, the answer is C. 640 square feet.

Answer 6

Find the area of the figure below.

5m+5m+5m+5m+3m

Here is an example of finding the area of a parallelogram.

A= base x height

Type only the number of square meters in the answer box.

Answer 7

To find the area of the figure, we add up all the sides:

5m + 5m + 5m + 5m + 3m = 23m

Therefore, the area of the figure is 23 square meters.

Answer 8

A new park is being built in the shape of a trapezoid, as show in the diagram below.

The builders will cover the ground with a solid rubber surface to ensure the children playing have a safe and soft place to land when they jump or fall.

How many square yards of rubber will be needed for this park?

10 yards+ 6.4 yards+ 20 yards+ 12.5 yards

Here is an example of how to solve for area of a trapezoid.

Please type only the number of square yards in the answer box. Your answer may include a decimal. Do not round.

Answer 9

To find the area of the trapezoid, we first need to find the average of the two parallel sides.

Average = (10 yards + 20 yards) / 2 = 15 yards

Then, we use the formula for the area of a trapezoid:

Area = (1/2) x (Sum of the bases) x (height)
Area = (1/2) x (10 yards + 20 yards) x 6.4 yards
Area = (1/2) x 30 yards x 6.4 yards
Area = 96 square yards

Therefore, 96 square yards of rubber will be needed for the park.