The sampleb1 has ph of 7.04 and total dissolve solid of 0 .001g

Question

Sample 2 has ph of 6.8 and total dissolve solid of 0.0025g
Sample 3 has pg of 6.05 and total dissolve solid of 0.0045g
And sample 4 has ph of 6.6 and total dissolve solid of 0.0024g
Which of these samples will undergo coagulation and flocculation process? Why?

Answer 1

Coagulation and flocculation are processes used in water treatment to remove suspended solids and impurities. These processes are influenced by pH levels and the concentration of total dissolved solids (TDS).

1. pH Level: Coagulation is most effective in a specific pH range, typically between 6.5 and 8.5 for many common coagulants (like aluminum sulfate or ferric chloride).

2. Total Dissolved Solids (TDS): Higher TDS can indicate a higher concentration of contaminants, which may require coagulation and flocculation to remove these impurities effectively.

Now, let's evaluate the samples based on their pH and TDS:

• Sample 1: pH = 7.04, TDS = 0.001 g - Suitable for coagulation and flocculation.
• Sample 2: pH = 6.8, TDS = 0.0025 g - Suitable for coagulation and flocculation.
• Sample 3: pH = 6.05, TDS = 0.0045 g - Low pH may limit coagulation effectiveness.
• Sample 4: pH = 6.6, TDS = 0.0024 g - Suitable for coagulation and flocculation.

Conclusion: Samples 1, 2, and 4 are likely to undergo coagulation and flocculation processes effectively due to their pH levels being within the suitable range and having low to moderate TDS. Sample 3 has a lower pH (6.05), which may not be optimal for coagulation, thus potentially limiting the effectiveness of the process.