The roots of

\[z^7 = -\frac{1}{\sqrt{2}} - \frac{i}{\sqrt{2}}\]are $\text{cis } \theta_1$, $\text{cis } \theta_2$, $\dots$, $\text{cis } \theta_7$, where $0^\circ \le \theta_k < 360^\circ$ for all $1 \le k \le 7$. Find $\theta_1 + \theta_2 + \dots + \theta_7$. Give your answer in degrees.

1 answer

I think I can read this as

z^7 = 1/√2 - 1/√2 i

so, that means

z^7 = cis 315°

z = cis(315/7)° = cis45° + k*360/7 for k=1..6
Similar Questions
  1. The roots of\[z^7 = -\frac{1}{\sqrt{2}} - \frac{i}{\sqrt{2}}\]are $\text{cis } \theta_1$, $\text{cis } \theta_2$, $\dots$,
    1. answers icon 0 answers
  2. Which fraction and decimal forms match the long division problem?15) 2.000 _1__5_ 50 45 ____ 50 45 ___ 5  A. \frac{2}{15}
    1. answers icon 0 answers
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions