The following equation is not a possible reaction; I wrote it only to show there is 1 mol Pb in 1 mol PbS.
PbS ==> Pb + S
We want 1000 g Pb. Convert to mols Pb.
mols Pb = grams/atomic mass = approx 4.8
Since the ratio of Pb to PbS is 1:1, then 4.8 = mols PbS we must start with. How many grams is that? mols = g/molar mass; therefore, g = mols x molar mass = approx 4.8 x about 239 = approx 1150 g PbS but since the ore contains only 84% PbS we must start with approx 1150/0.84 = ?g ore.
You must go through each step and calculate more accurately than I've estimated.
The rock in a lead ore deposit contains 84% PbS by mass. How many kilograms of the rock must be processed to obtain 1.0 kg of Pb?
I have no idea how to start or how I'm converting. Please help...
1 answer
1 answer