The matrix for reflecting across the line y = −x is given by:
[ 0 1 ]
[ 1 0 ]
The matrix for rotation by 330 degrees counterclockwise is equivalent to a rotation of 30 degrees clockwise. The matrix for that rotation is given by:
[ cos(30) sin(30)]
[-sin(30) cos(30)]
Since cos(30) = sqrt(3)/2 and sin(30) = 1/2, the matrix for a rotation of 30 degrees clockwise becomes:
[ sqrt(3)/2 1/2 ]
[-1/2 sqrt(3)/2]
The result of reflecting across the line y = -x and then rotating 330 degrees counterclockwise around the origin is obtained by the multiplication of the matrix for rotation by the matrix for reflection. That is,
T = Rotation Matrix * Reflection Matrix,
which gives:
T = [ sqrt(3)/2 1/2 ] * [ 0 1 ] = [ 1/2 sqrt(3)/2 ]
[-1/2 sqrt(3)/2] [ 1 0 ] [ sqrt(3)/2 -1/2 ]
Now, let's check the answer using the point (1, 1).
T * (1, 1) = [ 1/2 sqrt(3)/2 ] * (1, 1) = ( sqrt(2), 0)
[ sqrt(3)/2 -1/2]
I apologize, there actually seems to have been a mistake when calculating T. The matrix T is computed by multiplying every row in the first matrix by every column in the second matrix, so a correct calculation of T would actually result in:
T = [ 1/2 sqrt(3)/2 ]
[ sqrt(3)/2 -1/2 ]
Sorry about the earlier confusion!
The result of reflecting across the line y = −x and then
rotating 330 degrees counterclockwise around the origin is an
isometry T . Represent T by a 2 × 2 matrix. There is more than
one way to do it. Use the point (1, 1) to check your answer.
1 answer