Asked by gourav
The rest energy of a proton is 938 MeV. If its kinetic energy is also 938MeV, calculate its momentum and speed.
Answers
Answered by
TIRTH JOSHI
| Relativistic momentum | = 938MeV/c
gamma * m * v * c = 938MeV
gamma = 1 / sqrt(1 - (v/c)^2)
Solve for v. (don't worry about signs...)
You will probably need this conversion constant (if you want m/sec as a result), 938 MeV to kg...
1.672136811 x 10-27 kg
gamma * m * v * c = 938MeV
gamma = 1 / sqrt(1 - (v/c)^2)
Solve for v. (don't worry about signs...)
You will probably need this conversion constant (if you want m/sec as a result), 938 MeV to kg...
1.672136811 x 10-27 kg
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