According to Ohm's Law, which states \( V = IR \) (where \( V \) is voltage, \( I \) is current, and \( R \) is resistance), we can analyze what happens when the resistance \( R \) is halved.
If the resistance \( R \) is halved (let's say it changes from \( R \) to \( \frac{R}{2} \)) and assuming that the current \( I \) remains constant, the voltage \( V \) would be:
\[ V = I \cdot \frac{R}{2} = \frac{I \cdot R}{2} = \frac{V}{2} \]
However, if we assume that the voltage source remains constant while the resistance changes, the current will increase to maintain the same voltage. In this scenario, you would need to determine the new current based on your new resistance to find the new voltage.
So, if we strictly look at the options given and consider that voltage isn't defined to respond particularly to the change in resistance without additional context on how the circuit behaves (like constant current versus constant voltage scenarios), we can suggest:
If resistance is halved and voltage remains constant, the current increases, but the voltage itself stays the same when it is applied from a power source.
However, as the question is asked, normally under constant current conditions if you halve the resistance, the voltage would actually decrease.
Thus, the correct response based on the common context is: The voltage remains the same.
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