The region between the graphs of y=x^2 and y=3x is rotated around the line x=3. The volume of the resulting solid is

Answer 1

the curves intersect at (0,0) and (3,9). So,

v = ∫[0,3] 2πrh dx
where r=3-x and h=3x-x^2

or,

∫[0,9] π(R^2-r^2) dy
where R=(3-y/3) and r=(3-√y)

Answer 2

1080pi

Answer 3

mommy?