r^2 = 25 +25*3 = 100
so
r = 10
tan theta = sqrt3 in quadrant III
60 degrees below x axis
pi + pi/3 = 4 pi/3
you are in third quadrant because x and y are negative
The rectangular coordinates of a point are given (-5,-5root3). Find polar coordinates of the point. Express theta in radians.
Answer must be in form
(Type an ordered pair. Type an exact answer in terms of pi.Use integers or fractions for any numbers in the expression. Type the coordinate for theta in radians between 0 and 2pi)
My answer is (10,pi/3)but website is not accepting it . tell me mistake i am doing and the right answer
3 answers
my bad thank you sir
No problem :) You are welcome.