if w is the width, the length must be 4w+4
So, you need to solve
2(w + 4w+4) = 118
5w+4 = 59
w = 11
so the length is 48
The rectangle shown has a perimeter of 118 cm and the given area. Its length is 4 more than four times its width. Write and solve a system of equations to find the dimensions of the rectangle.
(rectangle has an area of 528 cm^2)
The length of the rectangle is ___ cm
The width of the rectangle is ___ cm
2 answers
Rectangle ABCD is similar to Rectangle WXYZ. The area of ABCD is 30 square inches. Explain how to find the area, x, of WXYZ.