The “reaction time” of the average automobile driver is about 0.7 s. (The reaction time is the interval between the perception of a signal to stop and the application of the brakes.) If an automobile can slow down with an acceleration of 12 ft/s^2 compute the total distance(in feet) covered in coming to a stop after a signal is observed from an initial velocity of 55 mi/h. Let 1 mi/h= 1.466 ft/s.

271 ft
327 ft
113 ft
414 f

I have absolutely no idea. If you could please show me what to do and how to get the answer and check my answer. That would be amazing! Thanks!

9 answers

distance before slowing: 55 *1.466ft/sec*.7sec=56.1ft check that.
distance while braking:
vf^2=vo^2+2ad
d= (55*1.466)^2/(2*12)=271ft

add the two distances
Thanks so much! You’re the GOAT!
Wait so is 271 the answer?
check it. Taking my answer is ridiculous. I am trying to show you how to work it.
and the answer is, no it is not the answer. Add the distances.
What distances? 12 and what else?
12 and 55?

If so, is the answer 338 which is not an answer choice.
56.1ft +271= ???
so whats the answer?