To balance the reaction of zinc (II) hydroxide with phosphoric acid, we will first write the unbalanced equation:
\[ \text{Zn(OH)}_2 + \text{H}_3\text{PO}_4 \rightarrow \text{Zn}_3\text{(PO}_4\text{)}_2 + \text{H}_2\text{O} \]
Now, to balance it out:
- Zinc (Zn) from zinc hydroxide and zinc phosphate must be balanced.
- Phosphate (PO₄) will appear as it needs to be balanced across both sides.
- Water will need to be balanced once the other components are balanced.
Ultimately, the balanced equation is:
\[ 3 \text{Zn(OH)}_2 + 2 \text{H}_3\text{PO}_4 \rightarrow \text{Zn}_3\text{(PO}_4\text{)}_2 + 6 \text{H}_2\text{O} \]
Thus, the coefficients are:
- Blank space 1: 3
- Blank space 2: 2
- Blank space 3: 1
- Blank space 4: 6
So, the completed response area is:
- Blank space 1: 3
- Blank space 2: 2
- Blank space 3: 1
- Blank space 4: 6
You would select the appropriate numbers from your provided answer options to complete the balance.