The reaction, N2O5 = 2NO2+1/2O2 is first order in N2O5 with rate constant 6.2 x 10^-4 s^-1. What is the value of rate of reaction when [N2O5] = 1.25 mol L^-1 s^-1 ?

Answer 1

rate = k(N2O5)^1
You know k and (N2O5) solve for rate. Note: I believe you meant (N2O5) = mols/L^-1.