The reaction for the complete combustion of acetylene is shown below.
C2H2(g) + 5/2 O2(g) -----------> 2 CO2(g) + H2O(l) ΔH = -1299 kJ
Use this reaction and the data below to calculate the heat of formation for acetylene.
ΔHf[H2O(l)] = -285.8 kJ/mol
ΔHf[CO2(g)] = -393.5 kJ/mol
1 answer
dHf rxn = (n*dHf products) - (n*dHf reactants). You have dHf rxn, plug in the dH for the CO2 and the H2O and calculate dHf C2H2.