well, if the temp rose, the reaction was exothermic (negative sign).
heat=-23.03*C*(53.67-15.21)
The reaction described takes place in solution in a coffe-cup style calorimeter. We will assume that the cups absorb or release a negligible amount of heat so we will not need to worry about the calorimeter constant or qcal.
If the total mass of the solution in the calorimeter is 23.03 g and and the solution increases from 15.21 °C to 53.67 °C, what is the value of q in joules for the reaction. Include the correct sign with your value of q. C = 4.179 J/g°C for the solution.
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