6 g is what part of a mole if a mole of K is 39 grams?
delta H = -437 kJ/mol for the reaction. So it will be how many kJ for the part of the mole K you have?
The reaction between potassium metal and chlorine gas is described by the following thermochemical equation K(s) + ½C_l2(g) = KCl(s) ÄH =–437 kJ mol–1
What will be the enthalpy change (to 2 significant figures) for the reaction when 6.0 g of potassium metal reacts with chlorine gas at constant pressure? The relative atomic mass of potassium is 39. ÄH =
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