rate=constant*a^2 ( b^3)
= constant*4* 1/8= 1/2 rate
the reaction A+3B—>2C+D is first order with respect to reactant A and second order with respect to reactant B if the concentration of A is doubled and the concentration of B is halved the rate of the reaction would---------------by a factor of-----------
3 answers
oops, thanks dr bob
rate=constant*a*b^3=1/4
rate=constant*a*b^3=1/4
if B is halved it should be 1.5 not 1/8 right