The ratio of “D”s to “A”s in the school was 8 to 21. If there were 572 As in the school this term, how many Ds were there?

1762

304

218

1502

1 answer

To find the number of D's based on the given ratio of D's to A's, we can set up a proportion.

The ratio of D's to A's is given as 8 to 21. We are told that there are 572 A's in the school this term.

Let's denote the number of D's as \( D \).

Using the ratio, \[ \frac{D}{A} = \frac{8}{21} \]

Substituting the value of A: \[ \frac{D}{572} = \frac{8}{21} \]

Now, we can cross-multiply to solve for \( D \): \[ 21D = 8 \times 572 \] \[ 21D = 4576 \]

Now divide both sides by 21: \[ D = \frac{4576}{21} \] \[ D = 218 \]

So, the number of D's in the school was \( \boxed{218} \).