The ratio of Ahmads savings to Azmans savings is 1:3. The average savings of the two boys is $34. Find the savings of each boy.

Answer 1

Let's denote the savings of Ahmad as A and the savings of Azman as B.

Given that the ratio of Ahmad's savings to Azman's savings is 1:3, we can write this as:

A/B = 1/3

We also know that the average savings of the two boys is $34, so:

(A + B)/2 = $34

Now we can substitute the ratio relationship into the average equation:

(1/3)B + B = 2 * $34
(1/3)B + 3/3*B = 2 * $34
(4/3)B = 2 * $34
(4/3)B = $68

Now we can solve for B:

B = (3/4) * $68
B = $51

Now that we have found Azman's savings, we can use the ratio relationship to find Ahmad's savings:

A = 1/3 * $51
A = $17

Therefore, Ahmad's savings is $17 and Azman's savings is $51.