ln (No/N) = kt
No = 0.620
N = 0.280
k = 0.340
Substitute and solve for t (in seconds)
The rate constant for this first‑order reaction is 0.340 s−1 at 400 ∘C.
A⟶products
How long, in seconds, would it take for the concentration of A to decrease from 0.620 M to 0.280 M?
1 answer
1 answer