Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
The Random Variable X is normally distributed with mean 560 and standard deviation 20.
Find P(X<530) which I calculated as 0.0668.
However...
It is known that p(|X-560|<a)
Find the value of a
1 answer