Ask a New Question

The random variable X has a PDF of the form

fX(x)={1x2,0,for x≥1,otherwise.

Let Y=X2 . For y≥1 , the PDF of Y it takes the form fY(y)=ayb . Find the values of a and b .

a=
b=

1 answer

a = 1/2
b = 3/2

Ask a New Question or answer this question.

Similar Questions

The random variable X is exponential with parameter λ=1 . The random variable Y is defined by Y=g(X)=1/(1+X) .a) The inverse
1. 4 answers
The random variable X is exponential with parameter λ=1 . The random variable Y is defined by Y=g(X)=1/(1+X) .a) The inverse
1. 1 answer
Let X be a random variable that takes non-zero values in [1,∞), with a PDF of the formfX(x)=⎧⎩⎨cx3 if x≥1,
1. 4 answers
Let X be a random variable that takes non-zero values in [1,∞), with a PDF of the formfX(x)=⎧⎩⎨cx3,0,if x≥1,otherwise.
1. 0 answers

more similar questions