The random variable X has a PDF of the form:
fX(x) = {1/x^2, for x >= 1,
0, otherwise.}
Let Y = X^2. For Y >= 1, the PDF of Y takes the form fY(y) = a/y^b. Find the values of a and b.
a =
b =
fX(x) = {1/x^2, for x >= 1,
0, otherwise.}
Let Y = X^2. For Y >= 1, the PDF of Y takes the form fY(y) = a/y^b. Find the values of a and b.
a =
b =