To model the situation with a two-variable inequality, we can define the variables as follows:
- Let \( x \) be the number of adult tickets.
- Let \( y \) be the number of children's tickets.
The cost of adult tickets is $15 per ticket, and the cost of children's tickets is $12 per ticket. The total amount they want to spend should not exceed $150. Thus, we can write an inequality to represent this situation:
\[ 15x + 12y \leq 150 \]
Next, we should consider the contextual constraints. Since the number of tickets cannot be negative, we have:
\[ x \geq 0 \quad \text{and} \quad y \geq 0 \]
Thus, the full set of inequalities that models the situation is:
\[ \begin{align*} 15x + 12y & \leq 150 \ x & \geq 0 \ y & \geq 0 \end{align*} \]
Now, let’s evaluate the potential solutions provided:
-
For the point (−3, 5):
- \( x = -3 \), which is not allowed since you cannot purchase a negative number of tickets. This point is not viable.
-
For the point (10, 5):
- Calculate the total cost: \[ 15(10) + 12(5) = 150 + 60 = 210 \]
- This exceeds the budget of $150. This point is not viable.
-
For the point (2, 5):
- Calculate the total cost: \[ 15(2) + 12(5) = 30 + 60 = 90 \]
- This is within the budget of $150. This point is viable.
-
For the point (3, 4.5):
- Since the number of children’s tickets (4.5) must be a whole number (you can't have half a ticket), this point is not viable.
Thus, the only viable solution from the given options is:
(2, 5).