1m^3/8.93*10^3kg * .0635kg/mol * 6.023*10^23atoms/mol = 4.2829*10^18 atoms
wow -- roughly 10^10 electrons per atom?
I don't think so. I suspect a typo.
The RAM of copper is 63.5g\mol and its density is 8.93×10^3kgm^3.in each cubic metre of the metal,there are 8.24×10^28free electrons. Calculate the number of free electrons contributed per atom
2 answers
Number of atoms per cubic meter =
(Mass per cubic meter/MM)*Avagadro's No.
= (8.93*10^3/63.5*10^-3)*6.022*10^23
= 8.4*10^28
Hence, the number of atoms in free electrons in each cubic meter are almost the same, and the answer is one.
(Mass per cubic meter/MM)*Avagadro's No.
= (8.93*10^3/63.5*10^-3)*6.022*10^23
= 8.4*10^28
Hence, the number of atoms in free electrons in each cubic meter are almost the same, and the answer is one.
1 answer