The radius r of a sphere is increasing at the uniform rate of 0.3 inches per second. At the instant when the surface area S becomes 100pi square inches, what is the rate of increase, in cubic inches per second, in the volume V?

Answer 1

V = 4/3 pi r^3
dV/dt = 4pi r^2 dr/dt
= A dr/dt
plug in the values given:

dV/dt = 100pi * .3 = 30pi

Answer 2

what is the volume of a cylinder of mozarella cheese, with radius z, and height a?
(don't use any exponents in your answer)

Answer 3

V = pir^2h
V = pizza
:)

Answer 4

22.5

Answer 5

V = 4/3 pi r^3
dV/dt = 4pi r^2 dr/dt
= A dr/dt ......................... YES
plug in the values given:

dV/dt = 100pi * .3 = 30pi .......... NO A = 4 pi r^2 = 100
so dV/dt = 100 * 0.3 = 30

Answer 6

Sorry, you are right, area = 100 pi
I missed that.