r = 6.955*10^5
v = 4/3 pi r^3
= 4/3 pi * 6.955^3 * 10^15
= 1.409 * 10^18
The radius of the sun is 695 500 km
What is its approximate volume written in Scientific notation?
4 answers
____ cubic meters, since r is in meters.
actually, since r is in km, that would be km^3
Assuming the sun is a sphere, we use the formula for the volume of a sphere:
V: 4/3π r^3
r = 695 500 = 6.955 × 10^5
π ≈ 3.14 = 3.14 × 10^0
4/3 ≈ 1.33 x 10^0
For the numbers, we get:
6.955^3 × 3.14 × 1.33 = 1,404.988249 = 1,405 to the nearest whole number.
For the powers, we get 5 + 5 + 5 + 0 + 0 = 15
Therefore the volume of the sun is approximately 1,405 × 10^15 km^3
But this is not in Scientific Notation, so we must rewrite 1,405 as 1.405 × 10^3
And the final answer is 1.405 × 10^18 km^3
(Note: The Sun is not a perfect sphere and the actual volume is 1.412 × 10^18 km^3)
(Mathopolis Questions)
V: 4/3π r^3
r = 695 500 = 6.955 × 10^5
π ≈ 3.14 = 3.14 × 10^0
4/3 ≈ 1.33 x 10^0
For the numbers, we get:
6.955^3 × 3.14 × 1.33 = 1,404.988249 = 1,405 to the nearest whole number.
For the powers, we get 5 + 5 + 5 + 0 + 0 = 15
Therefore the volume of the sun is approximately 1,405 × 10^15 km^3
But this is not in Scientific Notation, so we must rewrite 1,405 as 1.405 × 10^3
And the final answer is 1.405 × 10^18 km^3
(Note: The Sun is not a perfect sphere and the actual volume is 1.412 × 10^18 km^3)
(Mathopolis Questions)