The radius of the inscribed circle is 5. If the length of the hypotenuse of the right triangle ABC is 19, what is the perimeter of the triangle?

Answer 1

r = (a+b-c)/2
5 = (a+b-19)/2
a+b = 29

p = a+b+c = 19+29 = 48

Answer 2

It is very simple. 19+5+5.

Answer is 29pi

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