To subtract \(8.03 \times 10^{-8}\) and \(2.56 \times 10^{-2}\), we first need to express both numbers with the same power of 10.
Step 1: Convert to the Same Power of 10
The powers of ten are different: \(-8\) and \(-2\). We can convert \(2.56 \times 10^{-2}\) to a power of \(10^{-8}\) by moving the decimal point \(6\) places to the left.
\[
2.56 \times 10^{-2} = 2.56 \times 10^{-2} \times \frac{10^6}{10^6} = 2.56 \times 10^{-2 + 6} = 2.56 \times 10^4 \times 10^{-8} = 256000 \times 10^{-8}
\]
Thus, we rewrite \(2.56 \times 10^{-2}\) as:
\[
2.56 \times 10^{-2} = 256000 \times 10^{-8}
\]
Step 2: Rewrite Both Terms
Now we can rewrite both numbers using \(10^{-8}\):
- \(8.03 \times 10^{-8}\) remains \(8.03 \times 10^{-8}\).
- \(2.56 \times 10^{-2}\) is now \(256000 \times 10^{-8}\).
Step 3: Subtract the Two Numbers
We can convert \(2.56 \times 10^{-2}\) into the form \(0.0000256 \times 10^{-8}\):
So instead, we have:
\[
8.03 \times 10^{-8} - 0.0000256 \times 10^{-8} = (8.03 - 0.0000256) \times 10^{-8}
\]
Calculating the subtraction:
\[
8.03 - 0.0000256 = 8.0299744
\]
Final Step: Write the Result
Therefore, the result of the subtraction in scientific notation is:
\[
8.0299744 \times 10^{-8}
\]
If desired, we can approximate this to three significant figures:
\[
\approx 8.03 \times 10^{-8}
\]
But to keep all significant digits:
\[
\boxed{8.0299744 \times 10^{-8}}
\]