The radius of a circle is 6.20 times greater than the radius of a second circle. Compare the area of the larger circle with the area of the smaller circle.

Answer 1

Let's assume the radius of the smaller circle is r. Then, the radius of the larger circle is 6.20r.

The area of a circle is given by the formula A = πr^2, where A is the area and r is the radius.

The area of the smaller circle is A1 = πr^2, and the area of the larger circle is A2 = π(6.20r)^2 = π(38.44r^2).

To compare the two areas, we can divide A2 by A1:

A2/A1 = (π(38.44r^2))/(πr^2) = 38.44.

Therefore, the area of the larger circle is 38.44 times greater than the area of the smaller circle.