The radioactive nuclide 18F decays by first order kinetics with a half life of 1.83 hr.

How many hours will it take for 68.5% of a give quantity of 18F to decay?

1 answer

k for the decay = 0.693/1.83 = approx 0.4 but you need a better answer than that. Then,
ln(No/N) = kt
You can pick any number you like for No, then N is that number x (100-68.5) but I suggest you make it easy and do this.
No = 100
N = 31.5
k is from above
t = ? solve for this.
Remember to calculate k more accurately.