Asked by Molly
The radioactive nuclide 18F decays by first order kinetics with a half life of 1.83 hr.
How many hours will it take for 68.5% of a give quantity of 18F to decay?
How many hours will it take for 68.5% of a give quantity of 18F to decay?
Answers
Answered by
DrBob222
k for the decay = 0.693/1.83 = approx 0.4 but you need a better answer than that. Then,
ln(No/N) = kt
You can pick any number you like for No, then N is that number x (100-68.5) but I suggest you make it easy and do this.
No = 100
N = 31.5
k is from above
t = ? solve for this.
Remember to calculate k more accurately.
ln(No/N) = kt
You can pick any number you like for No, then N is that number x (100-68.5) but I suggest you make it easy and do this.
No = 100
N = 31.5
k is from above
t = ? solve for this.
Remember to calculate k more accurately.
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