The questions says it has 2 solutions. It wants me to find what x would be if cos(x)=-.49 and it is given that x is on the scale between 0 and 2pi.

I know that cosine is the x value, and since cosime is negative in this case the two solutions need to be in the 2nd and 3rd quadrants.
Would the correct way to do this be by making a right triangle and solving the sides?

2 answers

what angle has a cosine = .49 ??
cos^-1 .49 = 60.66 degrees
so our answers are 60.66 degrees above and below the negative y axis (180 deg)
180 - 60.66 = 119.34 degrees
180 + 60.66 = 240.66 degrees
0.00695
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