The question wants me to find sin(x/2) when cosx = -(12/13) in the interval (pi,3pi/2). I know that the eventual answer will be 5/sqrt26, however, I am not sure how to get there.

1 answer

the interval is Quad III , so x/2 will be in Quad II

sin(Θ/2) = ± √{[1 - cos(Θ)] / 2}
Similar Questions
  1. Solve this equation fo rx in the interval 0<=x<=3603sinxtanx=8 I would do it this way: sinxtanx = 8/3 sinx(sinx/cosx)=8/3
    1. answers icon 0 answers
    1. answers icon 5 answers
    1. answers icon 1 answer
  2. I have a question relating to limits that I solvedlim(x-->0) (1-cosx)/2x^2 I multiplied the numerator and denominator by
    1. answers icon 1 answer
more similar questions