Asked by b8
the question is what is the solution of the equation x+2/2=4/x?
1) 1 and-8
2)2 and-4
3) -1 and9
4) -2 and4
I did x^2+2x+8
(x+4)(x+2)
-4 -2
This is not one of the choices
can you help me figure out where I went wrong.
Thanks for your help
1) 1 and-8
2)2 and-4
3) -1 and9
4) -2 and4
I did x^2+2x+8
(x+4)(x+2)
-4 -2
This is not one of the choices
can you help me figure out where I went wrong.
Thanks for your help
Answers
Answered by
Reiny
I assume you meant
(x+2)/2 = 4/x
multiply each side by 2x , (sometimes called cross-multiplying)
x^2 + 2x = 8
x^2 + 2x - 8 = 0
(x+4)(x-2) = 0
x = -4 OR x = 2 , which is choice 2)
(if the way they presented the answer used the word AND, they they are technically incorrect.
x cannot be -4 AND 2 at the same time, but
x could be -4 OR 2.
btw, you lost your equal sign of the equation, that is where your error occurred.
(x+2)/2 = 4/x
multiply each side by 2x , (sometimes called cross-multiplying)
x^2 + 2x = 8
x^2 + 2x - 8 = 0
(x+4)(x-2) = 0
x = -4 OR x = 2 , which is choice 2)
(if the way they presented the answer used the word AND, they they are technically incorrect.
x cannot be -4 AND 2 at the same time, but
x could be -4 OR 2.
btw, you lost your equal sign of the equation, that is where your error occurred.
Answered by
b8
thank you for your help
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