Asked by Anonymous
the question is: an unknown substance has a vol. of 20ft^3 and weighs 3370 lb. What is the weight density?
I took 20ft^3 and converted it to 6.096m^3 and converted 3370 lb mass to 15165 Neutons so taking that divided by 6.096 m^3 I got 2,488 N/m^3. Is this correct.
Conversions 1 lb= 4.5 N and 1 ft. = .3048 m
I took 20ft^3 and converted it to 6.096m^3 and converted 3370 lb mass to 15165 Neutons so taking that divided by 6.096 m^3 I got 2,488 N/m^3. Is this correct.
Conversions 1 lb= 4.5 N and 1 ft. = .3048 m
Answers
Answered by
drwls
You can get the weight density in lb/ft^3 directly by dividing 3370 by 20. That would give you 168.5 lb/ft^3. The density of water in the same units is 62.4 lb/ft^3. Therefore the specific gravity (or mass density in g/cm^3) is 168.5/62.4 = 2.70. In kg/m^3 it is 2.7*10^3. In N/m^3 it is 26,460.
The conversion factor for lb to N is 4.45, not 4.5. You also missed a decimal point somewhere.
The conversion factor for lb to N is 4.45, not 4.5. You also missed a decimal point somewhere.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.