what's the trouble? Just plug in the values for t.
For example,
Q(800) = 300 e^(-0.000324*800) = 231.5006
The quantity Q of radioactive carbon remaining in a 300 - gram wood sample at time t is given by the expression
Q(t) = 300 e^{- 0.000324*t}.
How much radioactive carbon remains in the sample after
(a) 200 years, (b) 50000 years, (c) 125500 years?
2 answers
i just did it
Q(200) = 300 e^(-0.000324*200) = 281.176
But for b) and c) web work doesn't accept my answers
Q(50000) = 300 e^(-0.000324*50000) = 0.000028
maybe i should multiply by something...
Q(200) = 300 e^(-0.000324*200) = 281.176
But for b) and c) web work doesn't accept my answers
Q(50000) = 300 e^(-0.000324*50000) = 0.000028
maybe i should multiply by something...