Cl^- + Ag^+ ==> AgCl
mols Ag^+ = M x L = ?
Because of the 1:1 ratio
mols Cl^- = mols Ag^+.
Then g Cl^- = mols Cl- x atomic mass Cl-
The quantity of Cl- in a water supply is determined by titrating the sample with Ag+. What mass of chloride ion is present in a 10,0g sample of the water if 20.2 ml of 0.100 M Ag+ is required to react with all the chloride in the sample?
1 answer