To find the initial height from which the ball was dropped, we need to look at the constant term in the quadratic function. In this case, the constant term is 150, which means the ball was dropped from a height of 150 feet.
To find out when the ball hits the ground, we need to find the time when h(t) = 0. So we need to solve the equation:
-16.1t^2 + 150 = 0
Solving this equation, we get:
-16.1t^2 = -150
t^2 = 150/16.1
t^2 = 9.31677
t = √9.31677
t ≈ 3.05
Therefore, the ball hit the ground approximately after 3.05 seconds.
The quadratic function h(t) = -16.1t^2 + 150 models a ball's height, in feet, over time, in seconds,
after it is dropped from a 15 story building.
from what height, in feet, was the ball dropped?
after how many seconds, rounded to the nearest hundredth, did the ball hit ground?
3 answers
what about the first question
Apologies for that oversight.
The initial height from which the ball was dropped can be found from the constant term in the quadratic function, as mentioned earlier. In this case, the constant term is 150, which means the ball was dropped from a height of 150 feet.
Hence, the ball was dropped from a height of 150 feet.
The initial height from which the ball was dropped can be found from the constant term in the quadratic function, as mentioned earlier. In this case, the constant term is 150, which means the ball was dropped from a height of 150 feet.
Hence, the ball was dropped from a height of 150 feet.
1 answer