since the vertex is between the roots, we have
f(x) = a(x+2)(x-1 4)
Not sure what "1 4 " means, but now just plug in f(-1) = -5 to solve for a.
The quadratic function f is negative only on the open interval (−2, 1 4 ) and its graph passes through the point (−1, −5). Determine the coefficients of f.
1 answer