To factor the quadratic equation \(x^2 + 4x - 32 = 0\), we need to find two numbers that multiply to \(-32\) (the constant term) and add up to \(4\) (the coefficient of the linear term).
The two numbers that satisfy these conditions are \(8\) and \(-4\) because:
- \(8 \times (-4) = -32\)
- \(8 + (-4) = 4\)
Thus, the factored form of the equation is:
\[ (x + 8)(x - 4) = 0 \]
So the correct choice is:
\((x + 8)(x - 4) = 0\)