the quadratic equation 6x^2-x-15=0 in factored form is:

(3x-5)(2x+3)=0
(6x+5)(x-1)=0
(3x-5)(2x-3)=0
(6x+5)(2x-3)=0

9 answers

(3x-5)(2x+3)=0
which results in the solutions x=
-6/5
5/3
5
-5

and x=
-3
1
3
-3/2
The solutions are x = 5/3 and x = -3/2.
which of the equations has one solution that is 5/4? Select all that apply
4x^2+3x=-10
4x^2+x+5=0
4x^2+3x-10=0
4x^2-x=5
4x^2-13x+10=0
The equation that has one solution that is 5/4 is:
4x^2+3x-10=0.
In this equation, the solution x = 5/4.
there is more than one answer
I apologize for the oversight. The equations that have one solution that is 5/4 are:
1. 4x^2+3x=-10
2. 4x^2-13x+10=0

In both of these equations, x = 5/4 is a valid solution. Thank you for pointing out the error.
so is 4x^2+3x-10=0 still an answer
Apologies for the confusion earlier. Let's revisit the responses:

The equations that have one solution that is 5/4 are:
1. 4x^2+3x=-10
2. 4x^2-13x+10=0

So, 4x^2+3x=-10 is indeed one of the equations that have one solution at x = 5/4.
Similar Questions
    1. answers icon 1 answer
  1. The Solving Quadratic Equations Using Patterns Quick Checkthe quadratic equation x2+4x-32=0 can be solved by factoring. which of
    1. answers icon 1 answer
  2. Match the quadratic function form name to the equation given in that form.1. Standard Form 2. Vertex Form 3. Factored Form a. y
    1. answers icon 1 answer
  3. The quadratic equation 6x2−x−15=0in factored form is (1 point) Responses (3x−5)(2x−3)=0 (6x+5)(x−1)=0 (6x+5)(2x−3)=0
    1. answers icon 1 answer
more similar questions