To find the height \( h \) of the square pyramid using the Pythagorean Theorem in three dimensions, we can set up the necessary relationships between the height, the slant height, and half the length of the base.
Let's break down the problem:
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From the description, we know:
- The length of the base edge is 40 feet. Therefore, half of the base (which we need for our calculations) is: \[ \frac{40}{2} = 20 \text{ feet} \]
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The slant height \( s \) is given as 25 feet.
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The relationship we have is a right triangle formed by the height \( h \), half of the base (20 feet), and the slant height (25 feet). Using the Pythagorean Theorem: \[ s^2 = h^2 + \left(\frac{base}{2}\right)^2 \]
Plugging in the values, we get: \[ 25^2 = h^2 + 20^2 \]
This simplifies to: \[ 625 = h^2 + 400 \]
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Subtract 400 from both sides: \[ h^2 = 625 - 400 \] \[ h^2 = 225 \]
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Taking the square root of both sides, we find: \[ h = \sqrt{225} = 15 \text{ feet} \]
So the height \( h \) of the square pyramid is 15.0 ft. The correct response is:
15.0 ft.