The Pythagorean Theorem in Three Dimensions Practice

Question

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Question
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A square pyramid is shown. Its height is shown with a dotted line labeled 321 feet. Its slant height is shown with a dotted line labeled 436.5 feet. The variable l is shown along one of the edges of the square base.

The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base. Round the answer to the nearest tenth.

(1 point)
ft.

Answer 1

To find the length of the edge of the square base, we can use the Pythagorean theorem:

a^2 + b^2 = c^2

Where a and b are the two sides of the triangle formed by the height, slant height, and the edge of the base, and c is the hypotenuse (slant height).

In this case, one side of the triangle is the height (321 ft) and the other side is the length of the edge of the square base (l ft). The hypotenuse is the slant height (436.5 ft).

We can plug these values into the Pythagorean theorem:

321^2 + l^2 = 436.5^2

103041 + l^2 = 190522.25

l^2 = 190522.25 - 103041

l^2 = 87481.25

l = √87481.25

l ≈ 295.5 ft

So, the length of the edge of the square base is approximately 295.5 ft.

Answer 2

ALL THE ANSWERS FOR PRACTICE ILL PUT THE QUICK CHECK AS SOON AS I GET ALL THE RIGHT ANSWERS FOR THAT TOO:

1. 12
2. 40.3
3. 23
4. 591.6
5. 132.6

>_<

Answer 3

CREDIT GOES TO @mitskilover

1. 15.0
2. 59.5
3. 8.8
4. 9.1
5. 92.9

BYE :3 have a nice night.......

Answer 4

thx!

Answer 5

here are the answers to the questions<3
1.40
2.31.5
3.50
4.24
5.34.5
<3

Answer 6

@Bretothecat
all answers
WRONG I GOT A 0!!!