the puma, which can jump to a height of 12.9 ft when leaving the ground at an angle of 44°. With what speed, in SI units, must the animal leave the ground to reach that height?

Answer 1

The vertical component of velocity must be

Vf^2=2 g 12.9 where g=32ft/sec^2

Vf= sqrt(2*32*12.9)= 28ft/sec

so the velocity of the animal then is Vf/sin44 or about 28*1.4

you can do it more accurately.