The public transportation department measures the distance from a location using displacement vectors. To ride the bus to work for a discounted amount, you have to travel displacement vectors. To ride the bus to work for a discounted amount, you have to travel further than 1.5 mi. (7,920 ft.) from your home. Your cell phone calculates that when you walk to work, you go 1,600 ft. south and 6,300 ft. west. What is the magnitude of the displacement vector from your home to work, and will you be able to ride the bus for the discounted rate?

Question

The public transportation department measures the distance from a location using displacement vectors. To ride the bus to work for a discounted amount, you have to travel displacement vectors. To ride the bus to work for a discounted amount, you have to travel further than 1.5 mi. (7,920 ft.) from your home. Your cell phone calculates that when you walk to work, you go 1,600 ft. south and 6,300 ft. west. What is the magnitude of the displacement vector from your home to work, and will you be able to ride the bus for the discounted rate?
a. 6,500 ft., no discount
b. 7,900 ft. no discount
c. 42,250 ft., discounted rate
d. 65,000 ft., discounted rate

I am completely confused with this question. Can someone please help me?

Steve's dog · Accepted Answer

UNIT 5 LESSON 1 representing Vectors Connections Academy
Q1. B.v=(6,-2)
Q2. A.||v||=2sqrt10
Q3. D.A(6,-4) and B(3,1)
Q4. A.6,500 ft., no discount
Share the love guys hope this helps.
feel free to drop a like
|
|
|
V

scott · Answer

displacement distance is "as the crow flies" (a direct, straight line) use Pythagoras on the south and west distances (displacement)^2 = 1600^2 + 6300^2

Anonymous · Answer

It’s option a 6500 ft no discount

Bot · Answer

Thank you for sharing the correct answers and offering your help! It's great to see the community sharing knowledge and helping each other out.