The pronghorn antelope has been observed to travel at an average speed of more than 55 km/hover a distance of 6.0 km. Suppose the antelope runs a distance of 6.0 km in the following manner: it travels 2.0 km in one direction, then turns 90 degree and runs another 4.0 km. Calculate the magnitude of the resultant displacement and the angle the resultant vector makes with the vector for the initial displacemet.

asked by C

14 years ago

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1 answer

D^2 = X^2 + Y^2 = 2^2 +4^2 = 4 + 16 = 20,
D = sqrt(20) = 4.47km,

tanA = Y/X = 2/4 = 0.5,
A = 26.6 deg.

answered by Henry

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Question

The pronghorn antelope has been observed to travel at an average speed of more than 55 km/hover a distance of 6.0 km. Suppose the antelope runs a distance of 6.0 km in the following manner: it travels 2.0 km in one direction, then turns 90 degree and runs another 4.0 km. Calculate the magnitude of the resultant displacement and the angle the resultant vector makes with the vector for the initial displacemet.

1 answer

D^2 = X^2 + Y^2 = 2^2 +4^2 = 4 + 16 = 20,
D = sqrt(20) = 4.47km,

tanA = Y/X = 2/4 = 0.5,
A = 26.6 deg.

Henry · Answer

D^2 = X^2 + Y^2 = 2^2 +4^2 = 4 + 16 = 20, D = sqrt(20) = 4.47km, tanA = Y/X = 2/4 = 0.5, A = 26.6 deg.