The production of fruit juice at a free energy change of -345KJ/mol and equilibrium constant of 3.66x10^12 occurred at a temperature ......(Gas constant=8.314KJ/mol

A.273K
B.288K
C.200K
D.373K?

1 answer

To find the temperature at which the production of fruit juice occurs, we can use the equation:

ΔG = -RTln(K)

where ΔG is the free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.

First, let's rearrange the equation:

ΔG = -RTln(K)
-ΔG = RTln(K)
T = (-ΔG)/(Rln(K))

Now, let's plug in the given values:

ΔG = -345 KJ/mol
K = 3.66 x 10^12
R = 8.314 KJ/mol

T = (-345)/(8.314ln(3.66x10^12))
T ≈ 288

Therefore, the temperature at which the production of fruit juice occurs is approximately 288K.

The correct answer is B. 288K.