X = 1st. number, 3X = 2Nd number.
3X*X = 9 18/25
3X^2 = 9 18/25 = 243/25
X^2 = 243/75 = 81/25
X = sqrt(81/25) = 9/5 = 1 4/5 = 1st number
3X = 3 * 9/5 = 27/5 = 5 2/5 = 2Nd
number.
the product of two positive numbers is 9 18/25 and one of them is three times the other. find the numbers.
3 answers
Data:
let x and y are two possative numbers
xy = 9 18/25 = 243/25
x = 3y
calculate
x = ?
y = ?
Solution
xy = 243/25
3y.y = 243/25
3y2 = 243/25
divide 3 to both side
y2 = 81/25
square root to both side
y = 9/5
for x
x = 3y
x = 3.9/5
x = 27/5
hence two positive number are 9/5 and 27/5
let x and y are two possative numbers
xy = 9 18/25 = 243/25
x = 3y
calculate
x = ?
y = ?
Solution
xy = 243/25
3y.y = 243/25
3y2 = 243/25
divide 3 to both side
y2 = 81/25
square root to both side
y = 9/5
for x
x = 3y
x = 3.9/5
x = 27/5
hence two positive number are 9/5 and 27/5
1 4/5, 5 2/5