The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring.

Question

What is the constant of the quadratic expression in this equation?

x2 + x +
= 0

Answer 1

Let the two consecutive integers be \( x \) and \( x + 1 \). Therefore, their product can be expressed as:

\[ x(x + 1) = 420 \]

Expanding this gives:

\[ x^2 + x = 420 \]

To rewrite this in standard form, we need to move 420 to the left side of the equation:

\[ x^2 + x - 420 = 0 \]

In the equation \( x^2 + x - 420 = 0 \), the constant term is \(-420\).

Thus, the answer is:

\[ \text{Constant of the quadratic expression: } -420 \]